- Posts: 2
Power(W/m^2) versus Azimuth Angle (degree)
- ayedh_alqahtani
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                08 Feb 2013 22:41                #1259
        by ayedh_alqahtani
    
    
            
            
            
            
            
                                
    
                                                
    
        Power(W/m^2) versus Azimuth Angle (degree) was created by ayedh_alqahtani            
    
        Dear Dr. Paul,
I downloaded the latest version of SAM (2013.1.15), and I would like to get the curve that describes the Power (W/m^2) related to the Azimuth Angle (degree), for one PV module (any module), located in Columbus, OH. Similarly, I want another curve for the Power with the elevation angle. Could you please show me how to do this?
Thank you
Ayedh Alqahtani
The Ohio State University
PhD Student
    
    I downloaded the latest version of SAM (2013.1.15), and I would like to get the curve that describes the Power (W/m^2) related to the Azimuth Angle (degree), for one PV module (any module), located in Columbus, OH. Similarly, I want another curve for the Power with the elevation angle. Could you please show me how to do this?
Thank you
Ayedh Alqahtani
The Ohio State University
PhD Student
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- Paul Gilman
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                11 Feb 2013 15:10                #1260
        by Paul Gilman
    
    
            
            
            
            
            
                                
    
                                                
    
        Replied by Paul Gilman on topic Power(W/m^2) versus Azimuth Angle (degree)            
    
        In the incident-radiation-vs-azimuth.zsam file 
    (ZSAM 3 MB)
, I set up a parametric analysis on the azimuth angle with values between 90 and 270 degrees.
On the Results page, click Graph, and you should see a line graph of total annual input radiation (kWh) vs azimuth angle. You can convert the input radiation to W/m2 by dividing by 8,760 hours and the array area in m2.
If you click Tables on the Results page, you should see a table of hourly incident radiation (kW/m2) values for each azimuth angle. You can export that table to Excel (click Save as CSV or Send to Excel), sum up the 8,760 values in each column, and create a graph in Excel of the totals.
Best regards,
Paul.
    On the Results page, click Graph, and you should see a line graph of total annual input radiation (kWh) vs azimuth angle. You can convert the input radiation to W/m2 by dividing by 8,760 hours and the array area in m2.
If you click Tables on the Results page, you should see a table of hourly incident radiation (kW/m2) values for each azimuth angle. You can export that table to Excel (click Save as CSV or Send to Excel), sum up the 8,760 values in each column, and create a graph in Excel of the totals.
Best regards,
Paul.
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- ayedh_alqahtani
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                11 Mar 2013 09:23                #1261
        by ayedh_alqahtani
    
    
            
            
            
            
            
                                
    
                                                
    
        Replied by ayedh_alqahtani on topic Power(W/m^2) versus Azimuth Angle (degree)            
    
        Thank you Dr. Paul.    
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